From: Thomas Monjalon <thomas@monjalon.net>
To: "Medvedkin, Vladimir" <vladimir.medvedkin@intel.com>
Cc: "Kinsella, Ray" <ray.kinsella@intel.com>,
Syam Prasad N Pearson <syam.pearson@gadgeon.com>,
"users@dpdk.org" <users@dpdk.org>, "dev@dpdk.org" <dev@dpdk.org>,
"Wang, Yipeng1" <yipeng1.wang@intel.com>,
"Gobriel, Sameh" <sameh.gobriel@intel.com>,
"Richardson, Bruce" <bruce.richardson@intel.com>
Subject: Re: [dpdk-dev] Doubt regarding DPDK hash Library implementation
Date: Thu, 04 Nov 2021 17:49:51 +0100 [thread overview]
Message-ID: <3060108.LiUVKm96O0@thomas> (raw)
In-Reply-To: <6c1c908e-6a9a-c50d-0fa3-be61770ef97c@intel.com>
04/11/2021 17:39, Medvedkin, Vladimir:
> >> 01/11/2021 11:55, Syam Prasad N Pearson:
> >>> /** Number of items per bucket. */
> >>> *#define RTE_HASH_BUCKET_ENTRIES 8*
> >>>
> >>> defined inside:
> >>> dpdk-20.11.3/dpdk-stable-20.11.3/lib/librte_hash /rte_cuckoo_hash.h
> >>>
> >>> Why does the library take this value as *8*, is there any particular
> >>> reason for this? what if it is 16,32... etc.
>
> Yes, RTE_HASH_BUCKET_ENTRIES can be any power of 2.
> The reason for choosing 8 is a tradeoff between performance and memory.
> When it is equal to 8, the sizeof(struct rte_hash_bucket) equal to
> RTE_CACHE_LINE_SIZE, thus, there are no gaps in memory between the hash
> buckets due to their alignment.
That's a good comment to add in the code.
next prev parent reply other threads:[~2021-11-04 16:49 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2021-11-01 10:55 Syam Prasad N Pearson
2021-11-04 14:11 ` Thomas Monjalon
2021-11-04 14:46 ` Kinsella, Ray
2021-11-04 16:39 ` Medvedkin, Vladimir
2021-11-04 16:49 ` Thomas Monjalon [this message]
2021-11-06 23:23 ` Syam Prasad N Pearson
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