From: Syam Prasad N Pearson <syam.pearson@gadgeon.com>
To: Thomas Monjalon <thomas@monjalon.net>
Cc: "Medvedkin, Vladimir" <vladimir.medvedkin@intel.com>,
"Kinsella, Ray" <ray.kinsella@intel.com>,
"users@dpdk.org" <users@dpdk.org>, "dev@dpdk.org" <dev@dpdk.org>,
"Wang, Yipeng1" <yipeng1.wang@intel.com>,
"Gobriel, Sameh" <sameh.gobriel@intel.com>,
"Richardson, Bruce" <bruce.richardson@intel.com>
Subject: Re: [dpdk-dev] Doubt regarding DPDK hash Library implementation
Date: Sun, 7 Nov 2021 04:53:02 +0530 [thread overview]
Message-ID: <CAA2VcQiTG1oRKnHveBb4_oD=pLycWY3zd=5QFK4kXHB7Fr4DEw@mail.gmail.com> (raw)
In-Reply-To: <3060108.LiUVKm96O0@thomas>
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Thank you all.
On Thu, Nov 4, 2021 at 10:19 PM Thomas Monjalon <thomas@monjalon.net> wrote:
> 04/11/2021 17:39, Medvedkin, Vladimir:
> > >> 01/11/2021 11:55, Syam Prasad N Pearson:
> > >>> /** Number of items per bucket. */
> > >>> *#define RTE_HASH_BUCKET_ENTRIES 8*
> > >>>
> > >>> defined inside:
> > >>> dpdk-20.11.3/dpdk-stable-20.11.3/lib/librte_hash /rte_cuckoo_hash.h
> > >>>
> > >>> Why does the library take this value as *8*, is there any particular
> > >>> reason for this? what if it is 16,32... etc.
> >
> > Yes, RTE_HASH_BUCKET_ENTRIES can be any power of 2.
> > The reason for choosing 8 is a tradeoff between performance and memory.
> > When it is equal to 8, the sizeof(struct rte_hash_bucket) equal to
> > RTE_CACHE_LINE_SIZE, thus, there are no gaps in memory between the hash
> > buckets due to their alignment.
>
> That's a good comment to add in the code.
>
>
>
--
Regards,
Syam Pearson
Syam Pearson
Gadgeon Smart Systems
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prev parent reply other threads:[~2021-11-07 15:33 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2021-11-01 10:55 Syam Prasad N Pearson
2021-11-04 14:11 ` [dpdk-dev] " Thomas Monjalon
2021-11-04 14:46 ` Kinsella, Ray
2021-11-04 16:39 ` Medvedkin, Vladimir
2021-11-04 16:49 ` Thomas Monjalon
2021-11-06 23:23 ` Syam Prasad N Pearson [this message]
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